Win a $250 Mall of America gift card and a 3-night hotel stay in Bloomington
Bloomington Minnesota Travel & Tourism is hosting a 2026 Valentine’s Day Giveaway that promises a romantic experience for one lucky winner. The prize includes a three-night stay for two at the Sheraton Bloomington Hotel, dining at Lela Restaurant, and a $200 gift card to the Mall of America, applicable at various stores, restaurants, and attractions.
How to Enter
The giveaway is active from January 8, 2026, at 12:00 a.m. Central Time until February 11, 2026, at 11:59 p.m. Central Time. Eligible participants must be 21 years of age or older and reside in the United States or Canada, though residents from Quebec are excluded. Entry involves completing an online form that requires basic contact information and an answer to a hotel-related question. Participants are allowed only one entry per person each day.
A winner will be randomly chosen around February 12, 2026, and reached through email. Compliance with verification requirements is necessary, including form completion and valid ID submission. The prize must be experienced on dates set by the sponsor, with any extra travel costs or taxes being the winner's responsibility.
For comprehensive details and entry instructions, more information can be found on the Bloomington Minnesota Travel & Tourism website.
